# Recent Changes

1. 10:18 am

1. 2:19 pm

### Tuesday, April 17

1. Solving Quadratic Equations-Target D-Write Quadratics-Practice Problems edited ... \textbf{12)} \ x=3 \textbf{13)} \ x=\dfrac{2}{3}, x=5 \textbf{14)} \ x=\text{-}1, x=10, \…
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\textbf{12)} \ x=3
\textbf{13)} \ x=\dfrac{2}{3}, x=5
\textbf{14)} \ x=\text{-}1,x=10, \ x=\frac{1}{2}
\textbf{15)} \ x=\text{-}6, \ x=\text{-}1
\textbf{16)} \ x=\text{-}\dfrac{2}{3}
(view changes)
5:27 am
2. Solving Quadratic Equations-Target D-Write Quadratics-Practice Problems edited ... \textbf{12)} \ x=3 \textbf{13)} \ x=\dfrac{2}{3}, x=5 \textbf{14)} \ x=1, x=\text{-}1, \ …
...
\textbf{12)} \ x=3
\textbf{13)} \ x=\dfrac{2}{3}, x=5
\textbf{14)} \ x=1,x=\text{-}1, \ x=4x=\frac{1}{2}
\textbf{15)} \ x=\text{-}6, \ x=\text{-}1
\textbf{16)} \ x=\text{-}\dfrac{2}{3}
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5:27 am

### Sunday, April 15

1. Solving Quadratic Equations-Target C-Apply Quadratics-Practice Problems edited ... 4) Pictured below is a flowerbed that is 16 meters by 5 meters. You are hired to create a mulc…
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4) Pictured below is a flowerbed that is 16 meters by 5 meters. You are hired to create a mulch border that is going to create a total combined area for the bed and mulch to reach 250 square meters. What should the width of the mulch border be?
5) Below is an aerial view of the new doughnut shop that is opening in town. The red segments represent the footprint for the shop and outdoor seating which is 117 feet (East-West) by 108 feet (North-South). The blue segments represent what is going to be dedicated to parking. If the total lot size is 242 feet (East-West) by 233 feet (North-South), what is the width of the parking lot going to be (what is the length of x)?
Target Problems
6) Solve the following system:
2x - 5y = 8
x - y = 14
7) Graph the following linear equation:
y - 4 = - (x + 2)
8) Factor the following completely:
a) 2x2 + 13x - 24
b) 28x2 - 63
c) 3x2 - 3x - 36

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12:34 pm

### Sunday, April 1

1. Equations and Inequalities-Target B-Solving for What?-Practice Problems edited ... \textbf{1)} \ \ 2x+5y=10\\ \textbf{2)} \ \ \text{-}3x+9y=12\\ ... \ \ \dfrac{1}{2}x+4y=5\…
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\textbf{1)} \ \ 2x+5y=10\\
\textbf{2)} \ \ \text{-}3x+9y=12\\
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\ \ \dfrac{1}{2}x+4y=5\\\dfrac{1}{2}x-y=5\\
\textbf{4)} \ \ 3x+4y-7=0\\
Given the students work below, identify the mistake and correct the work.
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2:07 pm
2. Solving Quadratic Equations-Target A-Solving Quadratics-Practice Problems edited ... Answer Bank 31-40 You can use this calculator to solve the quadratic equations if you rewrite…
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You can use this calculator to solve the quadratic equations if you rewrite them in standard form: ax2+bx+c=0. If the graph is not displayed you may drag in any direction and pinch to zoom.
TargetedTarget Practice
41) Graph the following linear equation: 3x - y = 12
42) Solve the following equation: 2x - (x + 4) = 3x + 9
...
= x.
44) Find the x and y intercepts of 2x - 5y = 12.
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1:02 pm
3. Solving Quadratic Equations-Target A-Solving Quadratics-Practice Problems edited ... Answer Bank 31-40 You can use this calculator to solve the quadratic equations if you rewrite…
...
You can use this calculator to solve the quadratic equations if you rewrite them in standard form: ax2+bx+c=0. If the graph is not displayed you may drag in any direction and pinch to zoom.
Targeted Practice
41) Graph the following linear equation: 3x - y = 12
42) Solve the following equation: 2x - (x + 4) = 3x + 9
43) Given the following equation, y = 3x - 8, explain how it is different from the reference function: f(x) = x.
44) Find the x and y intercepts of 2x - 5y = 12.

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1:01 pm

### Sunday, March 11

DetermineTarget B: Determine an appropriate
{Home Investigations Test Graphic.PNG} {Home Guided Practice.jpg}
{Home Practice Problems Test Graphic.PNG}
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4:31 pm

### Monday, March 5

1. Polynomials-Target D-Bi and Trinomials-Practice Problems edited ... \textbf{11)} \ y^2+4y+12 \textbf{12)} \ 4x^2-36x+81 \textbf{13)} \ x^2-10y+25 x^2-10x+25 …
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\textbf{11)} \ y^2+4y+12
\textbf{12)} \ 4x^2-36x+81
\textbf{13)} \ x^2-10y+25x^2-10x+25
\textbf{14)} \ p^2-22p+121
\textbf{15)} \ z^2+16z-64
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10:49 am